-kcapm d!i% pAӘ Ƽ *DӘ`Ә `Ƽ 08<>CC ,`,  plm79@A,7: ,\First drag the point "Perimeter" to set the perimeter of the rectangle, then drag the point "Side" to see all rectangles with that perimeter.@97;0A90A9 L  pAF AN=tIn order for the area of a rectangle to equal its perimeter, the side lengths x and y must fulfill the relationship xy=2x+2y, i.e. y=2x/(x-2). For what values of the perimeter (2x + 2y) can this relationship hold?*,bd NSUREPANV@㪠TdDx!A$ p6BN R0@! S&h f R(Hn9n-J LN^NtNEWPASTONVH(n.CC N N >(#@@ 0p2  T0@S@@/0NJSG Gl`J`H@ @d>@0;NP||||CC@<1N l" p5 Xyzp vzp ,$檐zCCCB?(\)0N " p4 Xxʃ@CCD C?QC!H?= p  PerimeterDQ8$C c!H  p Perimeter4D橠 ho?橰`DDQ8$CCC?d6Me $S!X pD Lark Poar Ve@0LD\C c!XM0  pkM0NMNM0HHCCD\C? !>, p SideCԈC c!!@  pX4D橠 ho?橰`DCԈCCC?  '  pl{V‚g/,T`A / PNYO mB P/(?0 o P/H_CԈD\CԈB:>? .V pc1HHPU0VCԈCC8?5%F?5%F *6v pm1pv Kv  X = *A*AP`*A*A*A*AL`&L|J&&Length(Segment X) = EP02&TTh@L@g d303$ M@@3@ W K$Z@`  s g0~/33J!0``~ d  Z p FZHH[0CԈC 8  W pm2 KƼ Calculator KƼL {D:2{!:*}X}{X 2} = *AP`*A*A*A*AL`&L|J&&.2*Length(Segment X)/(Length(Segment X) 2) = TTh@L@g d303$ M@@3@ W K$Z@`  s g0~/33J!0``~ d  !(  pY槐zpCԈC 8CԈC?\( '  pmw?<N?<VNnHnN n/ / |p.?B'HmCR8C 8D,FVC 8?(_&]'4p?FZHH[0 5A pm3 E4  g l P P Y = {!:*}X}{X 2} = *AP`*A*A*A*AL`&L|J&&Length(Segment Y) = (Length(Segment X) 2) = TTh@L@g d303$ M@@3@ W K$Z@`  s g0~/33J!0``~ d  p;2x/(x-2)CE"C 4di^ pG^HH_0CC 8 JV pm6 CalculatorРLР  2{!:*}X + 2{!:*}Y = *AP`*A*A*A*AL`&L|J&& Perimeter = nt Y) = (Length(Segment X) 2) = TTh@L@g d303$ M@@3@ W K$Z@`  s g0~/33J!0``~ d ?K pm5p  Y{!:*}X = 2{!:*}Y = *AP`*A*A*A*AL`&L|J&&Area = er = nt Y) = (Length(Segment X) 2) = TTh@L@g d303$ M@@3@ W K$Z@`  s g0~/33J!0``~ d f  pp1tr@0s0p?CԈCCCCC 8CԈC 8 c!i/  pq o P/H\O _(HJg,/,YO/.?0 o P/H\O _/(/N^YO/.CCCC 8?cYOu  pn>(&`YO mB P/(?0 oP/H\O _(H l&P0+:m^2+:m ] CC 8CԈC 8?<_ [('4p?H >Ƽ (` >Ƽ 08<>(