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Geometry Problem of the Week

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Aim at This Target!
March 30 - April 3, 1998

I have enjoyed reading your solutions to my shotgun target problems, so I have another one for you.

I'm constructing another target for long-range shooting. The target will have a six-inch diameter black bull's-eye, and concentric circles with diameters of 12", 18", and 24" respectively, to form alternating white and black bands. There is also a 24" square circumscribed about the outermost circle. Got it? Okay.

What is the area of the bull's-eye and what is the area of each of the white and black bands making up the target? (There are four areas to determine - the bull, two white bands, and one black band.)

While we're at it, what's the area between the 24" outer circle and the 24" square?

What do you notice about the relation between the area of each section and the band just outside it?

EXTRA: Now that you're warmed up, can you identify WHY the relation in the last question exists? (You might want to try some similar setups with targets of different sizes to see if that helps.)

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Solutions

Annie says:

Finding the areas this week wasn't too much of a problem for most of you, though some of you didn't read carefully and you found the area of all the circles, not just the bands. 78 folks got it right, and 64 got it wrong.

Most of those who got it wrong neglected to include a statement about the relation between consecutive regions. I wasn't looking for anything fancy with that, I just wanted you to notice that there was a constant increase in area as you went from the bull's-eye to the outer ring. This could take many different forms. The most common ones were that the difference is 18pi, or 56.5, or that the difference was equivalent to two bull's-eyes - that's a good observation! Some people pointed out that the areas were odd multiples of 9pi - 1, 3, 5, 7. It's good to be able to see patterns like that in your work.

The bonus was to try to figure out why this relation existed. A number of people took a stab at it. I have included two of the solutions below - those of Jenny Kaplan of Castilleja Middle School and Jason Chiu of Laramie Junior High School. Give them a read.

When doing a problem like the bonus, it's a good idea to throw in some x's instead of numbers and see if you can get it to work out algebraically. For example, represent the area of one ring as x^2pi - (x-3)^2pi. That's one circle minus the circle with a radius of 3 less. Then represent the next ring with (x+3)^2pi - x^2pi. When you work those out, you'll find that the difference between the two is 18pi.

The next time that I use a problem like this (maybe it will be next year), I might not give credit to people who use "pie" instead of "pi." It's a simple thing, and it shows that you have some understanding of what pi is - it's a symbol that looks sort of like this - TT - that is a letter in another alphabet (Greek), and since the TT symbol is hard to write sometimes, we spell the word out by saying pi. "Pi" stands for a particular number, and it's important that you use it correctly.

A list of all the people who got this problem right follows the highlighted solutions below, and most of the solutions are also available.




From:   Jason Chiu
        
Grade:  9
School: Laramie Junior High School, Laramie, Wyoming

     Using the formula A=pi*r^2, the area of each circle can be found.  The 
radius of the circles are 3, 6, 9, and 12 inches, which makes their areas 9*pi, 
36*pi, 81*pi, and 144*pi, respectively.  The area of the bull's-eye is 9*pi 
(inner circle); the first white ring (inner) is pi(36-9)=27*pi; the black ring 
is pi(81-36)=45*pi; and the outer white ring is pi(144-81)=63*pi.
     The area of the 24 inch to a side square is 24^2=576, and that minus the 
area of the largest circle is 576-144*pi.
     The area increases proportionally to the increase of the radius of the 
circle.  Because the increase of the radius is constant in this case, the 
pattern is constant.
     I will have a mathematical proof to answer this part of the problem.  I 
will prove that it is linearly increasing if c is.  Let the inner circle (of the 
two) have radius x and the increase be a constant, c.  So the area of the band 
is pi((x+c)^2-x^2), which simplifies to pi(2cx+c^2).  It is linear because the 
degree of the only x is 1.  It is increasing linearly and if that is, then the 
relationship happens.



From:   Jenny Kaplan
        
Grade:  7
School: Castilleja Middle School, Palo Alto, California

I gave each of the different bands or circle a number.
Starting with the bulls eye as 1, each of the next bands
had the next numbers. The area of number 1 (or the bulls-
eye) is 9pi.  The area of number 2 is 27pi.  The area of 
number 3 is 45pi, and the area of number 4 is 63pi. Each
of these numbers was found from taking band that you want
to find the area’s of area and subtracting the area of the
circles inside it.  

The area between the outer square and the circle inside it
is 576 - 144pi.  This was found by subtracting the area of
the circle from the area of the square.

For this next question I thought of everything in terms of
a multiple of 9. Therefore the area of each circle was 9*1pi,
9*4pi, and 9*9pi.  The areas of the corresponding bands are
9*3pi, 9*5pi, and 9*7pi. I have noticed 2 things.  The first
one is that all of the circles are 9 times each consecutive
square.  The second thing is that each of the bands have a 
difference of 18pi between them (as well has having 9 times the
next consecutive odd numbers).

EXTRA:
First I looked at the pattern with the circles, and found out
why they are 9 times each consecutive square number. All of the
radii of the circles given are divisible by 3.  To then find the
area you square the 3 as well as the number that 3 was multiplied
by. If you were to take out all of the 9s then you would be left
with the squares of all of the other numbers.  They happen to be
consecutive squares because each of the radii were either 3*1,
3*2, 3*3, or 3*4.
For the pattern of the bands this is what I did:  If you look at
the pattern, you will see that you skip all of the even multiples
of 9.  Since there is a difference of 9 between each power, there
is a difference of 18 between all of the odd multiples of 9 in this
pattern.




The following students submitted correct solutions this week:

Mark Yang, Grade 7, Alki Middle School, Vancouver, Washington
Tiffanie Lam, Grade 8, Sequoia Middle School, Pleasant Hill, California
Aaron Mertz, Grade 8, Plum Grove Junior High School, Rolling Meadows, Illinois
Gordon Bockus Jr., Grade Freshman, Eastern Oklahoma State College, Wilburton, Oklahoma
Natasha Fedner, Grade 9, Bexley High School, Bexley, Ohio
Jessi Kennedy, Grade 9, Amador Valley High School, Pleasanton, California
Michelle Hrdina, Grade 10, South Kitsap High School, Port Orchard, Washington
Joey Fenton, Grade 10, South Kitsap High School, Port Orchard, Washington
Aaron Ogletree, Grade 10, South Kitsap High School, Port Orchard, Washington
Glen Melnik, Grade Teacher, Piedmont Independent Learning High School, Oakland, California
Katsu Sato, Grade 6, Troy Intermediate School, Avon Lake, Ohio
Catherine Mangasi, Grade 12, Wilburton High School, Wilburton, Oklahoma
Curt Henn and Matt Henn, Grade 9, Bexley High School, Bexley, Ohio
Josh Boyette, Grade 10, Akiba Hebrew Academy, Merion, Pennsylvania
Abby Lindsay , Grade 6, Troy Intermediate School, Avon Lake, Ohio
Dan and Steve, Grade 6, Troy Intermediate School, Avon Lake, Ohio
Amber Jensen, Grade 5, Crystal Springs Elementary
Arielle Cohen, Grade 10, Akiba Hebrew Academy, Merion, Pennsylvania
Lauren Brown, Grade 9, Hudson's Bay High School, Vancouver, Washington
Sarah Hesson, Grade 10, Mount Saint Joseph Academy, Flourtown, Pennsylvania
DeDe DiDonato, Grade 10, Mount Saint Joseph Academy, Flourtown, Pennsylvania
Joseph Bovard, Grade 9, Hudson's Bay High School, Vancouver, Washington
Chris Lauber, Grade 9, Smoky Hill High School, Aurora, Colorado
Kim Harris, Grade 8, Albright Middle School, Houston, Texas
Crystal Cannaday, Grade 9, Franklin County High School, Rocky Mount, Virginia
Jason Shertzer and Karl and Sean and Jeff, Grade 9, Skyview High School, Vancouver, Washington
Jonathan Emmons and Amey Adkins, Grade 9, Franklin County High School, Rocky Mount, Virginia
Melanie, Grade 9, Skyview High School, Vancouver, Washington
Jacob Casey, Grade 9, Skyview High School, Vancouver, Washington
Victor Hsieh, Grade 9, Hudson's Bay High School, Vancouver, Washington
Isaiah Wyckoff, Grade 9, Skyview High School, Vancouver, Washington
Jessica Barclay-Strobel, Grade 10, Oak Park and River Forest High School, Oak Park, Illinois
Avrum Tilman, Grade 10, Akiba Hebrew Academy, Merion, Pennsylvania
Chester Chan, Grade 6, Odle Middle School, Bellevue, Washington
Kristin Loyd, Grade 8, Discovery Middle School, Vancouver, Washington
Jia-Xin Wang, Grade 9, American Embassy School, New Delhi, India
Hannah Margoles, Grade 10, Akiba Hebrew Academy, Merion, Pennsylvania
Nicky Kim, Grade 10, American Embassy School, New Delhi, India
Jason Chiu, Grade 9, Laramie Junior High School, Laramie, Wyoming
Alex Chen, Grade 7, Odle Middle School, Bellevue, Washington
Jenny Kaplan, Grade 7, Castilleja Middle School, Palo Alto, California
Ryan Bates, Grade 9, Skyview High School, Vancouver, Washington
Mary Park, Grade 8, Odle Middle School, Bellevue, Washington
Alessandro Binotti, Grade , American Embassy School, New Delhi, India
Kristen Lee, Grade 9, Highland Park Senior High School, St. Paul, Minnesota
Tova Gardner and Brianna Sterling, Grade 9, Highland Park Senior High School, St. Paul, Minnesota
Maja White, Grade 9, Highland Park Senior High School, St. Paul, Minnesota
Clayton, Grade , Redmond High School, Redmond, Oregon
Peter Lindgren, Grade , Farila Skola, Farila, Sweden
C. G., Grade 9, Germantown Academy, Fort Washington, Pennsylvania
Emily Castor, Grade 9, Granada High School, Livermore, California
Lyrica Hubbard, Grade , Redmond High School, Redmond, Oregon
Alison Miller, Grade 6, homeschooled, Niskayuna, New York
Chaim Bloom, Grade 10, Akiba Hebrew Academy, Merion, Pennsylvania
Sarah Kress, Grade 9, Mount Saint Joseph Academy, Flourtown, Pennsylvania
Kevin Palmer, Grade 9, Granada High School, Livermore, California
Sundhar Ramalingam, Grade 9, Southeast Raleigh High School, Raleigh, North Carolina
Tanya Colburn, Grade 10, Mount Saint Joseph Academy, Flourtown, Pennsylvania
Anna Warszawa, Grade 9, Germantown Academy, Fort Washington, Pennsylvania
Laura Roos, Grade 10, Shaler Area High School, Pittsburgh, Pennsylvania
Alex Chernyavsky, Grade , Akiba Hebrew Academy, Merion, Pennsylvania
Abin Bandy, Grade , Germantown Academy, Fort Washington, Pennsylvania
Abin Bandy, Grade 9, Germantown Academy, Fort Washington, Pennsylvania
Thomas Kuo, Grade 10, Burroughs High School, Ridgecrest, California
Jennifer Liang, Grade 8, Odle Middle School, Bellevue, Washington
Niki Weber, Grade 10, Shaler Area High School, Pittsburgh, Pennsylvania
Lauren Rossi and Anne Hines, Grade , Germantown Academy, Fort Washington, Pennsylvania
Catalina Anghel, Grade 11, Mackenzie High School, Deep River, Ontario, Canada
Teneal Dollar, Grade 10, Shelby County High School, Columbiana, Alabama
Jackie Garner, Grade 11, Shelby County High School, Columbiana, Alabama
Erika Mitchell, Grade 11, Shelby County High Schoo, Columbiana, Alabama
Katy Crumpton, Grade 10, Shelby County High School, Columbiana, Alabama
Julie Dennis, Grade 10, Shelby County High School, Columbiana, Alabama
Christy Thornburg, Grade 10, Shelby County High School, Columbiana, Alabama
Frannie Laks, Grade 10, Akiba Hebrew Academy, Merion, Pennsylvania
Alex Morgovsky, Grade , Akiba Hebrew Academy, Merion, Pennsylvania
Lia LaBrant, Grade 8, Discovery Middle School, Vancouver, Washington
Zimran Douglas, Grade 12, Wingate High School, Brooklyn, New York

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