## BEATCALC:  Beat the Calculator!

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 From B. Lee Clay

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### Multiplying a repeating 9's number by 88

1. Choose a repeating 9's number (at least three digits long -- 999, etc.)
2. Multiply it by 88
3. The product is:
- the first two digits are 87
- the next digits are repeating 9's (two fewer than repeating 9's in the original number)
- the last two digits are 12

#### Example:

1. If the first number is 8888:
2. Multiply by 88. The product is:
- the first two digits are 87: 87.
- the next digits are repeating 9's (two fewer than repeating 9's in the original number): 99.
- the last two digits are 12: 12.
3. So 9999 × 88 = 879912.

See the pattern?

1. If the first number is 999999:
2. Multiply by 88. The product is:
- the first two digits are 87: 87.
- the next digits are repeating 9's (two fewer than repeating 9's in the original number): 9999.
- the last two digits are 12: 12.
3. So 999999 × 88 = 87999912.