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Topic: 12 billiard ball problem
Replies: 15   Last Post: Jan 4, 2013 12:07 PM

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Rosa Guia

Posts: 1
Registered: 12/12/04
reply to "12 billiard ball poblem"
Posted: Jan 7, 1998 7:02 AM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

Mr. Jonathan Pearce,
Please don't think me impolite for answering your question about

the 12 billiard ball problem.
You can determine the heavier ball by:
weighing #1
place the balls on a platform balance where there are 6 on
each pan. If one pan is heavier than the other, it means that the
heavy billiard ball is one of the 6 balls.
weighing #2
get the 6 balls and place them on the balance once again,but
this time there must be 3 balls on each pan. If one pan is heavier,
the billiard ball must be there, so
weighing #3
put 2 of the 3 remaining balls on each pan. If one is heavier
than the other then that must be the ball you're looking for. If the 2
balls have equal weights then the remaining one must be the one you're
looking for.
I know this may be kind of weird because you may already have
the answer to your question, but I enjoyed answering it.
Thank you.

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