Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: 12 billiard ball problem
Replies: 15   Last Post: Jan 4, 2013 12:07 PM

 Messages: [ Previous | Next ]
 Rosa Guia Posts: 1 Registered: 12/12/04
reply to "12 billiard ball poblem"
Posted: Jan 7, 1998 7:02 AM

Mr. Jonathan Pearce,

the 12 billiard ball problem.
You can determine the heavier ball by:
weighing #1
place the balls on a platform balance where there are 6 on
each pan. If one pan is heavier than the other, it means that the
heavy billiard ball is one of the 6 balls.
weighing #2
get the 6 balls and place them on the balance once again,but
this time there must be 3 balls on each pan. If one pan is heavier,
the billiard ball must be there, so
weighing #3
put 2 of the 3 remaining balls on each pan. If one is heavier
than the other then that must be the ball you're looking for. If the 2
balls have equal weights then the remaining one must be the one you're
looking for.
I know this may be kind of weird because you may already have
Thank you.

Date Subject Author
11/18/97 Jonathan Pearce
11/18/97 Sam @ The NIMP Team
11/19/97 jhnieto@luz.ve
11/19/97 Sam @ The NIMP Team
11/18/97 Pat (Jedi In Training)
11/18/97 H. Peter Anvin
11/19/97 David Kastrup
11/19/97 jhnieto@luz.ve
3/3/99 bob vanderbrink
3/3/99 David Kastrup
11/20/97 Jeff Erickson
11/20/97 Brian Hutchings
1/7/98 Rosa Guia
11/10/98 James W.
10/27/03 Bill Bridges
1/4/13 Raymond C Phillips, LT USN Retired