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reply to "12 billiard ball poblem"
Posted:
Jan 7, 1998 7:02 AM
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Mr. Jonathan Pearce,
Please don't think me impolite for answering your question about
the 12 billiard ball problem.
You can determine the heavier ball by:
weighing #1
place the balls on a platform balance where there are 6 on
each pan. If one pan is heavier than the other, it means that the
heavy billiard ball is one of the 6 balls.
weighing #2
get the 6 balls and place them on the balance once again,but
this time there must be 3 balls on each pan. If one pan is heavier,
the billiard ball must be there, so
weighing #3
put 2 of the 3 remaining balls on each pan. If one is heavier
than the other then that must be the ball you're looking for. If the 2
balls have equal weights then the remaining one must be the one you're
looking for.
I know this may be kind of weird because you may already have
the answer to your question, but I enjoyed answering it.
Thank you.
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