
Re: See How do the alleged top genius mathematicians cheat the so innocent students?
Posted:
Oct 4, 2017 2:34 AM


????? ????????? 4 ?????? ?.?. 2017 13 ?????? 28 ???? 22 ?????? UTC+7, Mr Sawat Layuheem ????????: > ????? ????????? 4 ?????? ?.?. 2017 13 ?????? 23 ???? 43 ?????? UTC+7, bassam king karzeddin ????????: > > On Tuesday, October 3, 2017 at 12:21:17 PM UTC+3, bassam king karzeddin wrote: > > > On Monday, July 31, 2017 at 9:07:07 PM UTC+3, bassam king karzeddin wrote: > > > > On Monday, July 31, 2017 at 8:16:08 PM UTC+3, bassam king karzeddin wrote: > > > > > How so illegally do the alleged top most genius mathematicians fabricate a real root for this unsolvable Diophantine Equation (n^5  m^5 = nm^4)? > > > > > Where (n, m) are positive integers, no wonder for sure! > > > > > > > > > > Big Hint for clever students, (see the very EASY proof in my posts) > > > > > > > > > > Regards > > > > > > > > Bassam King Karzeddin > > > > > 07/31/2017 > > > > > > > > Of course, any wise student or wise mathematician would realize immediately by factoring the right side that this Diophantine Eqn. has no solution in positive integers or generally in nonzero integers and finished (that is all for sure) > > > > so by factoring the RHS, you get: > > > > > > > > (n  m)*(n^4  mn^3 +(mn)^2  nm^3 + m^4) = nm^4 > > > > > > > > It is quite easy to see that if gcd(n, m) = k, then the whole Eqn. becomes as a multiple of (k^5), where then you get the same original Eqn. in coprime integers for (n & m), hence gcd(n, m) = 1, without any loss of generality > > > > > > > > So, let (k = n  m), where (k) is coprime integer to both (n & m) > > > > > > > > So, you have (k) divides the LHS, BUT doesn't divide the RHS, hence no integer solution exists (FINISHED) > > > > ************************************************ > > > > But the word exist is never understood by any top most genius mathematicians on earth, they insist deliberately to make real root solution from nothingness, otherwise, how can they create huge volumes of so unnecessary and baseless mathematics that a clever student can collapse so easily now, wonder! > > > > > > > > Then how? > > > > > > > > A genius would simply suggest dividing the whole Eqn. by (m^4), then he would simply get the following rational polynomial as ((n/m)^5  (n/m) + 1), and completing his cheating, he would denote the simple fraction (n/m) equals to (x), then magically the same original Eqn. becomes as a polynomial of an odd degree (5) that MUST have at least one real root exactly in this form > > > > > > > > (x^5  x + 1 = 0), then the play goes on approximating that imagined in mind for real root (but never existing as proved above), and of course in a constructible form and particularly in the rational or decimal form that has, of course, no end, since no solution exists for the same original Diaphotine Eqn.) > > > > > > > > And the very poor mind would be so thrilled by few or say 10 digits or many more of accuracy solution > > > > > > > > And to escape the so embarrassment, they would simply tell you yes the complete solution is really real but be staying there at their fake paradise called (INFINITY) > > > > > > > > And not only that they would go much further obeying the FTG obtaining all the other complex roots (where this silly game had been refuted and well exposed so badly in my many posts) > > > > > > > > Enough cheating especially in mathematics for sure > > > > > > > > BKK > > > > > > > > > > > > On Monday, July 31, 2017 at 9:07:07 PM UTC+3, bassam king karzeddin wrote: > > > > On Monday, July 31, 2017 at 8:16:08 PM UTC+3, bassam king karzeddin wrote: > > > > > How so illegally do the alleged top most genius mathematicians fabricate a real root for this unsolvable Diophantine Equation (n^5  m^5 = nm^4)? > > > > > Where (n, m) are positive integers, no wonder for sure! > > > > > > > > > > Big Hint for clever students, (see the very EASY proof in my posts) > > > > > > > > > > Regards > > > > > Bassam King Karzeddin > > > > > 07/31/2017 > > > > > > > > Of course, any wise student or wise mathematician would realize immediately by factoring the right side that this Diophantine Eqn. has no solution in positive integers or generally in nonzero integers and finished (that is all for sure) > > > > so by factoring the RHS, you get: > > > > > > > > (n  m)*(n^4  mn^3 +(mn)^2  nm^3 + m^4) = nm^4 > > > > > > > > It is quite easy to see that if gcd(n, m) = k, then the whole Eqn. becomes as a multiple of (k^5), where then you get the same original Eqn. in coprime integers for (n & m), hence gcd(n, m) = 1, without any loss of generality > > > > > > > > So, let (k = n  m), where (k) is coprime integer to both (n & m) > > > > > > > > So, you have (k) divides the LHS, BUT doesn't divide the RHS, hence no integer solution exists (FINISHED) > > > > ************************************************ > > > > But the word exist is never understood by any top most genius mathematicians on earth, they insist deliberately to make real root solution from nothingness, otherwise, how can they create huge volumes of so unnecessary and baseless mathematics that a clever student can collapse so easily now, wonder! > > > > > > > > Then how? > > > > > > > > A genius would simply suggest dividing the whole Eqn. by (m^4), then he would simply get the following rational polynomial as ((n/m)^5  (n/m) + 1), and completing his cheating, he would denote the simple fraction (n/m) equals to (x), then magically the same original Eqn. becomes as a polynomial of an odd degree (5) that MUST have at least one real root exactly in this form > > > > > > > > (x^5  x + 1 = 0), then the play goes on approximating that imagined in mind for real root (but never existing as proved above), and of course in a constructible form and particularly in the rational or decimal form that has, of course, no end, since no solution exists for the same original Diaphotine Eqn.) > > > > > > > > And the very poor mind would be so thrilled by few or say 10 digits or many more of accuracy solution > > > > > > > > And to escape the so embarrassment, they would simply tell you yes the complete solution is really real but be staying there at their fake paradise called (INFINITY) > > > > > > > > And not only that they would go much further obeying the FTG obtaining all the other complex roots (where this silly game had been refuted and well exposed so badly in my many posts) > > > > > > > > Enough cheating especially in mathematics for sure > > > > > > > > BKK > > > > > > Did you see clearly how a fiction solution (by fictional endless alleged real numbers) was simply imposed (without confessing the fact) for the impossibility of the solution of this Diophantine Eqn. (n^5  m^5 = nm^4), by cheating and inventing polynomials from nothing to nothing > > > > > > The urgent question: > > > > > I wrote: > > > > > Are you so stupid (mathematicians) up to this limit? wonder! > > > > I meant (genius mathematicians only) > > > > BKK > > > > > > Or more precisely, do you love to be so ignorant and dreaming for the rest of your meaningless life? wonder! > > > > > > BKK > > To My teacher....from me > https://www.facebook.com/photo.php?fbid=882425365245789&set=pcb.882425538579105&type=3&theater > > > https://www.facebook.com/photo.php?fbid=882402661914726&set=a.397252653763065.1073741825.100004350013006&type=3&theater > > You invites me to SCI ask My crazy Problem....no sites in the worlds accept me.... > But SCI welcome me ....thanks teacher....
Teacher BASSAM, https://www.facebook.com/photo.php?fbid=882039511951041&set=a.397252653763065.1073741825.100004350013006&type=3&theater
Why 1/3 can slide to infinity????? why????
We in TwoActions Tree Spaces or not ?
https://www.facebook.com/photo.php?fbid=882005125287813&set=a.397252653763065.1073741825.100004350013006&type=3&theater

