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KBH
Posts:
200
Registered:
3/14/10


Re: Don't Bogart that Square Root of 2
Posted:
Oct 5, 2017 6:32 PM


> Then continuing to the operational goal: > > C as the Diagonal^2 or as any value > > Square Root of C = Square Root of (C/2) * 1.414214... > Square Root of C = Square Root of (C/4) * 1.414214^2 > Square Root of C = Square Root of (C/8) * 1.414214^3 > . > . > .
or
Square Root of C = Square Root of (C/2) * 1.414214... Square Root of C = Square Root of (C/4) * 2 Square Root of C = Square Root of (C/8) * 2 * 1.414214... Square Root of C = Square Root of (C/16) * 4 Square Root of C = Square Root of (C/32) * 4 * 1.414214... Square Root of C = Square Root of (C/64) * 8 . . .
It began as transforming a right triangle to square legs while holding the diagonal length.
Then it just becomes a basic operation of
Square Root of C = Square Root of (C*x) * (1/Square Root of x) .
The square root of 2 makes a table of values:
Square Root of 2 = 1.414214... Square Root of 8 = 2 * 1.414214... Square Root of 32 = 4 * 1.414214... Square Root of 128 = 8 * 1.414214...
But square foundations have been dated at about 10,000 years ago and so the square root of 2 was probably measured and used.


Date

Subject

Author

10/5/17


KBH

10/5/17


KBH

10/5/17


KBH


