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Topic: Sci.math morons still struggling to prove that m+n is ALWAYS a
factor of New Calculus derivative!

Replies: 1   Last Post: Nov 8, 2017 6:28 PM

 Python Posts: 378 Registered: 8/16/16
Re: Sci.math morons still struggling to prove that m+n is ALWAYS a
factor of New Calculus derivative!

Posted: Nov 8, 2017 6:28 PM

John Gabriel wrote:
> On Wednesday, 8 November 2017 18:07:27 UTC-5, John Gabriel wrote:
>> On Wednesday, 8 November 2017 17:57:03 UTC-5, John Gabriel wrote:
>>> On Wednesday, 8 November 2017 17:22:37 UTC-5, Python wrote:
>>>> John Gabriel wrote :
>>>>> On Wednesday, 8 November 2017 15:24:01 UTC-5, Python wrote:
>>>>>
>>>>> <a lot of bullshit I don't care to address>
>>>>>

>>>>>> There is actually a counter example you've always evading,
>>>>>> x -> e^(-1/x^2) at x = 0

>>>>>
>>>>> That's not a counterexample you stupid! m+n is a factor of every term in the numerator.

>>>>
>>>> Mmmh, this is so obvious that you've shown it in your answer.
>>>>
>>>> Oh, dear, you didn't.
>>>>
>>>> How weird :-)

>>>
>>> Oh really? Let's see how wrong you are:
>>>
>>>
>>> Just because YOU are not able to do it, does not mean it cannot be done.
>>>
>>> FAIL (again!)

>>
>> And just to shut your mouth:
>>

> ... that article was from 2002 !!!!!!

1st fact: Last modification of document: 00:05 9 nov. 2017

2nd fact: irrelevant anyway

3rd fact: the point is about to find the derivative at x=0 of this
function, with your lousy "new-calculus", this is the question