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Topic:
A limit at a point means a function is continuous at that point, but orangutans still don't get it!
Replies:
1
Last Post:
Nov 9, 2017 6:02 PM




Re: A limit at a point means a function is continuous at that point, but orangutans still don't get it!
Posted:
Nov 9, 2017 6:02 PM


Woa bird brain Jon Gabriel:  Expert in long posts, with a lot of bla bla  Expert in Google docs with complicated unelegant proofs  Expert in YouPoop videos with a lot of handwaving and nonsense
Congratulations, your man boob kingdom might come.
Am Donnerstag, 9. November 2017 23:20:51 UTC+1 schrieb John Gabriel: > On Thursday, 9 November 2017 07:50:03 UTC5, John Gabriel at age 50. wrote: > > There is **no limit** to e^(1/(x^2)) as x approaches 0. > > > > The idiotic mainstream tendency is to transfer the limit to the exponent, that is, > > > > oo = Lim_{x \to 0} 1/(x^2) > > > > in which case we say there is no limit because oo is NOT a limit. > > > > Then what do orangutans do? They say: > > > > 0=e^(oo) > > > > treating infinity exactly as if it were a number. Chuckle. I wonder ... does the limit operator jump back and forth between the exponent and e .... > > > > As I've stated in the past and continue to state, you cannot have a HOLE in a function at a point c in an interval (a,b) if the function is continuous on the interval and has a limit at c. The bogus mainstream calculus NEEDS holes, but even then, it needs a lot more decrees to stay afloat. > > > > Therefore, the function e^(1/(x^2)) has NO limit at x=0 otherwise it would be continuous at x=0. > > > > And you thought Swiss cheese was holey eh?! > > > > Wolfram computational engine states that the limit is 0. Tsk, tsk. Idiots... > > > > Eat shit and die Mr. Penis Messager (Jean Pierre Messager / alias Python). > > https://www.youtube.com/watch?v=4ZNMaPo5TMQ



