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Topic: A limit at a point means a function is continuous at that point,
but orangutans still don't get it!

Replies: 1   Last Post: Nov 9, 2017 6:02 PM

 bursejan@gmail.com Posts: 5,511 Registered: 9/25/16
Re: A limit at a point means a function is continuous at that point,
but orangutans still don't get it!

Posted: Nov 9, 2017 6:02 PM

Woa bird brain Jon Gabriel:
- Expert in long posts, with a lot of bla bla
- Expert in Google docs with complicated unelegant proofs
- Expert in YouPoop videos with a lot of handwaving and nonsense

Congratulations, your man boob kingdom might come.

Am Donnerstag, 9. November 2017 23:20:51 UTC+1 schrieb John Gabriel:
> On Thursday, 9 November 2017 07:50:03 UTC-5, John Gabriel at age 50. wrote:
> > There is **no limit** to e^(-1/(x^2)) as x approaches 0.
> >
> > The idiotic mainstream tendency is to transfer the limit to the exponent, that is,
> >
> > -oo = Lim_{x \to 0} -1/(x^2)
> >
> > in which case we say there is no limit because -oo is NOT a limit.
> >
> > Then what do orangutans do? They say:
> >
> > 0=e^(-oo)
> >
> > treating infinity exactly as if it were a number. Chuckle. I wonder ... does the limit operator jump back and forth between the exponent and e ....
> >
> > As I've stated in the past and continue to state, you cannot have a HOLE in a function at a point c in an interval (a,b) if the function is continuous on the interval and has a limit at c. The bogus mainstream calculus NEEDS holes, but even then, it needs a lot more decrees to stay afloat.
> >
> > Therefore, the function e^(-1/(x^2)) has NO limit at x=0 otherwise it would be continuous at x=0.
> >
> > And you thought Swiss cheese was holey eh?!
> >
> > Wolfram computational engine states that the limit is 0. Tsk, tsk. Idiots...
> >
> > Eat shit and die Mr. Penis Messager (Jean Pierre Messager / alias Python).

>