The 3-rd definition is as follows, he says m(t) is a **trend function**, iff we have:
a) f(t)-f(s) = m(t) (t-s)
b) m(.) is continuous at s
It is then the case that f'(s)=m(s).
Am Freitag, 10. November 2017 21:20:34 UTC+1 schrieb John Gabriel: > On Sunday, 29 October 2017 20:02:00 UTC-4, John Gabriel at age 50. wrote: > > "But what about my 'Certificate of the memorization of many details'? Surely that's more important than silly independent thought!" - Jan Burse, Zelos Malum > > > > I am sorry you poor retards. May I suggest wiping your arses with it? > > > > Bwaaa haaaa haaaa! > > > > Comments are unwelcome and will be ignored. > > > > Posted on this newsgroup in the interests of public education and to eradicate > > ignorance and stupidity from mainstream mythmatics. > > > > email@example.com (MIT) > > firstname.lastname@example.org (HARVARD) > > email@example.com (MIT) > > firstname.lastname@example.org (David Ullrich) > > email@example.com > > firstname.lastname@example.org > > A monkey with a PhD is a monkey no less.