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Topic: If a^2 + b^2 – a + b – c = a^2 + b^2, and c is <
ab/3, then a^2 + b^2 is prime

Replies: 8   Last Post: Nov 11, 2017 11:37 PM

 Messages: [ Previous | Next ]
 richard miller Posts: 170 Registered: 9/29/06
Re: If a^2 + b^2 – a + b – c = a^2 + b^2, and c
is < ab/3, then a^2 + b^2 is prime

Posted: Nov 11, 2017 7:57 AM

On Saturday, 11 November 2017 12:38:26 UTC, 4mus...@gmail.com wrote:
> True or False?

Are you sure that is what you mean?

a^2 + b^2 - a + b - c = a^2 + b^2

subtracting a^2 + b^2 from both sides implies

- a + b - c = 0

rearranging

c = b - a

Fair enough, perhaps, but a^2 + b^2 can be anything you like.

I presume a re-post is on its way?

Richard Miller
http://www.urmt.org

Date Subject Author
11/11/17 4musatov@gmail.com
11/11/17 richard miller
11/11/17 4musatov@gmail.com
11/11/17 4musatov@gmail.com
11/11/17 4musatov@gmail.com
11/11/17 richard miller
11/11/17 4musatov@gmail.com
11/11/17 Bill
11/11/17 4musatov@gmail.com