The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » Math Topics » geometry.pre-college

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: construction of triangle of given perimeter, given point and angle
Replies: 16   Last Post: Jun 10, 2011 12:58 PM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
Peter Ash

Posts: 13
Registered: 12/6/04
Re: parabola through 4 points
Posted: Nov 17, 1997 8:53 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply


Thanks for your response. I don't fully understand your argument,

Michael Keyton wrote:
> Peter has asked about finding the foci of a hyperbola knowing 5 points
> that lie on the hyperbola. I can not fully solve this, but I can find the
> center of the hyperbola. For the ellipse, I can find both the center and
> the foci. I think some extension about this construction should work for
> the hyperbola, but it is not yielding itself to me quickly.
> Ellipse: Construct any chord of the ellipse, construct a parallel chord.
> The line through the midpoints of two parallel chords passes through the
> center. (I do not know a proof of this without adding a point at infinity
> and looking at poles. I can give a reasonable argument using symmetry of
> the ellipse, but it lacks the proper rigor.) Repeat for a second chord,
> the interesection of the two lines is the center of the ellipse. This also
> works for finding the center of teh hyperbola.

I agree that the line through the midpoints of two parallel chords of
conic passes through the center of the conic. (Proof: The projective
that fixes the center of the conic and maps it to a circle takes
segments to segments, parallel lines to parallel lines, and midpoints of
segments to midpoints of segments.) But given five arbitary points on a
conic, how do you get two parallel chords? Am I missing something

> Construct any circle centered at this point that intersects the ellipse in
> 4 points (use the five points, 3 can't be the vertices of the minor axis.)
> The perpendicular bisectors of the consecutive pairs of points are the
> major and minor axis. (In the hyperbola case, this will find the axis for
> the foci) Use compass and straightedge, knowing the relationships between
> the distance between the foci and the center and the semi-major and minor
> axis lengths fill find the foci length. This can be constructed easily.

How do you locate the points of intersection between a circle centered
the center of the conic and the conic? And then how do you find the
intersections of the axes with the ellipse? Once you've got that, of
course you are right, its easy to find the foci.

> Unfortunately, for the hyperbola where is the length of the minor axis?

It would seem you would have to know the asymptotes.

> Michael Keyton
> St. Mark's School of Texas

Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.