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Topic: to prove: rays bisecting 3 angles of a triangle meet at a single point
Replies: 6   Last Post: Feb 10, 1999 10:10 AM

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 Guy F. Brandenburg Posts: 333 Registered: 12/3/04
Re: center of gravity formula
Posted: May 19, 1998 9:41 PM

Imrich Miklosko wrote:

> We have an isosceles triangle with 2 sides equal to 100 cm. We have
> figured out the third side to be equal to 1.7453292. We need to know
> the formula to figure out the center of gravity of this triangle. I
> know how to draw the intersection point of the three angles, now I
> need to find out the distances of the intersection points. ___x___ ___
> \ / | r\ /r | \ / | V \ | --- Any advice would be appreciated. Thanks

That's a mighty skinny triangle! The center of gravity is simply the
point where the 3 medians meet. By the way, that point (the centroid) is
also 2/3 of the way from any vertex to the midpoint of the opposite
side. I hope this helps.

Date Subject Author
12/27/97 Eileen Stevenson
12/28/97 Michael Keyton
12/28/97 Floor van Lamoen
12/28/97 Guy F. Brandenburg
5/16/98 Imrich Miklosko
5/19/98 Guy F. Brandenburg
2/10/99 AWatsonNY@aol.com