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Topic: ? angle bisector of triangle divides opposite side in proportion to other 2 sides ?
Replies: 4   Last Post: Mar 4, 1998 10:46 AM

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Eileen Stevenson

Posts: 2
Registered: 12/6/04
? angle bisector of triangle divides opposite side in proportion to other 2 sides ?
Posted: Feb 28, 1998 10:17 AM
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I can't seem to prove this:

B
.
/|\
/ | \
c / | \ a (This is not supposed to be isosceles
/ | \ This will make a better picture viewed via a
/ | \ fixed width font such as Courier New. )
A/_____|_____\C
d Z e
|<-----b----->|

Given an _arbitrary_ triangle ABC with AZ bisecting angle ABC, and lengths
labeled as shown,
length of AB = c,
length of BC = a,
length of AC = b,
length of AZ = d,
length of CZ = e;
then:
d/c = e/a.

Please help. I am tutoring a bright HS student who has this as a
postulate in his text. It has been too many years since all those college
math courses I took...

Thanks in advance,
Charles Stevenson
eks@worldpath.net
stevenc@hlthsrc.com





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