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Posts:
200
Registered:
12/6/04
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Re: Trisection
Posted:
Jul 16, 2002 8:59 AM
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Thanks for the hard work Eric.
> I have algebraically checked this construction. It will effectively
converge
> to the trisection, with a cubic convergence rate. More precisely, if
we take A
> as the origin and C as the unit point on the X axis, 3*t the angle
to trisect,
> if h is the difference in abscissa between the first guess and the
result
> (i.e. the
> difference in cosine), and h' the same difference after one
iteration, we have:
>
> h' = h^3 / (48*sin(t)^2) + O(h^4)
I was unable to follow your suggestion for finding a longer
construction line so I found my own (see below).
In response to John's suggestion of relettering, I am reposting my
construction based on AOB.
>[It might also be
a good idea to change the lettering, since, to the extent that
>there's a
standard, it's usually an angle AOB that gets trisected.]
Near Exact Trisection:
1. Start with an unknown angle <90 deg., label the vertex O.
2. Draw an arc with origin at O crossing both lines of the angle at
points A and B.
3. Draw line AB making an isosceles triangle.
4. Using point A as the origin, draw an arc crossing line AB and the
earlier arc somewhere between ü and ý way between points A and B.
Label where this new arc crosses line AB point D.
Label where this new arc crosses the first arc point E.
5. Draw line DE and extend it well past O . If line DE passes
exactly through point O (it wonÃÂt) stop, your first guess was an exact
trisection.
6. Extend line OA well past point O, step off 3 times length OA from
point O and label the new point F.
7. Swing an arc of length OF with O as the origin that crosses the
extended line DE near point F.
Label the intersection G.
8. Draw line GO and extend it to intersect the original arc from step
2.
Label the intersection EÃÂ.
Line OEÃÂ is a good trisection. However this is only the start.
Repeating the process from step 4 using AEÃÂ as the arc radius results
in a trisection to within 10E-11 degrees. Each subsequent iteration
improves the trisection by several orders of magnitude.
It takes an extra step, but an alternate construction using a line
from point B perpendicular to line OA (line AB is no longer necessary)
yields exactly the same results if your step 4 circle has its origin
at point B, is between 1/2 and 3/4 angle AOB, and point D is on the
new perpendicular line instead of line AB. This gives a longer working
line for the construction.
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