
Re: Conditional Probability Question
Posted:
Sep 29, 2001 9:19 PM


>Subject: Re: Conditional Probability Question >From: Virgil vmhjr2@home.com >Date: 9/29/01 5:24 PM Central Daylight Time >Messageid: <vmhjr2B18A42.16335629092001@news1.denver1.co.home.com> > >In article <9p5cca$gshuu$1@ID99058.news.dfncis.de>, > "David LloydJones" <davidlj@sympatico.ca> wrote: > >> "Mensanator" <mensanator@aol.com> wrote >> > >> > Are you aware of the basic fact that the sum of probabilities must be 1? >> > >> >> Mensanot, >> >> The sum of probabilities for simultaneously and exhaustively possible >events >> must sum to one. >> >> At each stage of the investigation of the parts, bad and good is an >> exhaustive list of the possibilities. The chance of part i being bad is >> 1/(101i). The chance of the part being good is {1[1/(101i)]} , for >> a total of 1. >> >> Why don't you trot off and help Harris with his FLT proof? >> >> dlj. >> >Are you 2 aware that you are both beating the same dead horse?
Yeah, but since he called me stupid and dopey, I insist on having the last word.
But you are right, there is no point in pursuing this argument any further.

