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Re: Conditional Probability Question
Posted:
Sep 29, 2001 9:19 PM
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>Subject: Re: Conditional Probability Question
>From: Virgil vmhjr2@home.com
>Date: 9/29/01 5:24 PM Central Daylight Time
>Message-id: <vmhjr2-B18A42.16335629092001@news1.denver1.co.home.com>
>
>In article <9p5cca$gshuu$1@ID-99058.news.dfncis.de>,
> "David Lloyd-Jones" <davidlj@sympatico.ca> wrote:
>
>> "Mensanator" <mensanator@aol.com> wrote
>> >
>> > Are you aware of the basic fact that the sum of probabilities must be 1?
>> >
>>
>> Mensanot,
>>
>> The sum of probabilities for simultaneously and exhaustively possible
>events
>> must sum to one.
>>
>> At each stage of the investigation of the parts, bad and good is an
>> exhaustive list of the possibilities. The chance of part i being bad is
>> 1/(101-i). The chance of the part being good is {1-[1/(101-i)]} , for
>> a total of 1.
>>
>> Why don't you trot off and help Harris with his FLT proof?
>>
>> -dlj.
>>
>Are you 2 aware that you are both beating the same dead horse?
Yeah, but since he called me stupid and dopey, I insist on having the last
word.
But you are right, there is no point in pursuing this argument any further.
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