Drexel dragonThe Math ForumDonate to the Math Forum



Search All of the Math Forum:

Views expressed in these public forums are not endorsed by Drexel University or The Math Forum.


Math Forum » Discussions » Education » math-teach

Topic: Uncl: Re: Uncl: card game
Replies: 3   Last Post: Aug 18, 1995 5:52 PM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
Ted Alper

Posts: 51
Registered: 12/6/04
Re: Uncl: Re: Uncl: card game
Posted: Aug 18, 1995 5:52 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply


>To Ted Alper and others wondering about the dice and equal probablities. Here
>are the dice:
> Die one: 1,2,3,4,5,6
> Die two: 0,0,0,6,6,6
> Die three: 0,0,6,6,12,12
> And die four is an octahedron with sides 0,0,6,6,12,12,18,18


>Then depending on which 2 die you roll you have 1 to 24 and can combine more
>to get higher numbers.


OK -- I guess what you mean is you roll die one always and
(a) pair it with die two to get 1 -- 12 with equal probability
(b) pair it with die three to get 1 -- 18 with equal probability
(c) pair it with die four to get 1 -- 24 with equal probability

When you say "combine more to get higher numbers" you won't have
equal probabilities any more if you use any of dice two three and
four together.

(Of course there are other ways to construct/label dice to get equiprobable
outcomes.)


Ted Alper
alper@ockham.stanford.edu






Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© Drexel University 1994-2014. All Rights Reserved.
The Math Forum is a research and educational enterprise of the Drexel University School of Education.