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Re: Radius algorithm
Posted:
Dec 5, 1996 8:17 AM


Marcus wrote:
>Thank you for your help. What you have described is exactly what I'm >currently doing, however its not very robust when noisy data is >introduced into the algorithm. Do you know how to do a least squares >fit of data to the equation of a circle? (I suppose: f(x,y)=x^2+y^2) >I have a suspicion that this is a multivariate regression problem. I'm >rather a newbie to this sort of thing. > >Thanks, >Marc
Hello, it's me again! You told me that my solution to your problem was the same as the one you were already using. Then I believe that your original description was a bit wrong, but that won't help you any further. I spent some time on a least squares method and I found one. I will not repeat the derivation here since that would give me a headache typing it, but I will give you the final result:
Suppose that you have datapoints (x1,y1), (x2,y2), ..., (xN,yN). Now form the following sums:
M00 = N M10 = x1+x2+...+xN M20 = x1^2+x2^2+...+xN^2 M30 = x1^3+x2^3+...+xN^3
M01 = y1+y2+...+yN M11 = x1*y1+x2*y2+...+xN*yN M21 = x1^2*y1+x2^2*y2+...+xN^2*yN
M02 = y1^2+y2^2+...+yN^2 M12 = x1*y1^2+x2*y2^2+...xN*yN^2
M03 = y1^3+y2^3+...+yN^3
As you can see the first index of M gives you the power of the x's within the summation, and the second one of the y's.
Now the quantities you want are the center (X,Y) of the circle and it's radius R. They can be given by: ( + M00^2*M02*M30  M00*M01^2*M30 + M00^2*M12*M02  M00*M12*M01^2 + ) (  M20*M10*M00*M02  M00*M02^2*M10  M00^2*M21*M11 + M00*M21*M01*M10 + ) (  M00^2*M03*M11 + M00*M03*M01*M10 + M20*M01*M00*M11 + M02*M01*M00*M11 ) X =  2 * ( + M00^2*M20*M02  M00*M01^2*M20  M00*M10^2*M02 + ) (  M00^2*M11^2 + 2*M00*M01*M10*M11 )
( + M00^2*M21*M20 + M00^2*M03*M20  M20^2*M00*M01  M00*M20*M01*M02 + ) (  M00*M10^2*M21  M00*M10^2*M03  M00^2*M30*M11  M00^2*M12*M11 + ) ( + M00*M10*M11*M20 + M00*M11*M02*M10 + M10*M01*M00*M30 + M01*M10*M00*M12 ) Y =  2 * ( + M00^2*M20*M02  M00*M01^2*M20  M00*M10^2*M02 + ) (  M00^2*M11^2 + 2*M00*M01*M10*M11 )
R^2 = X^2 + Y^2 + M20/M00 + M02/M00  2*M10/M00*X  2*M01/M00*Y
Now I hope I didn't make any mistakes typing it. I've checked this formula for the data points (2,1), (3,4), (1,2) and (6,5). It does indeed give X=3, Y=1 and R=5, as it should. I believe that my derivation is correct. Use it, try it out and tell me when anything is wrong with it.
More greetings from Dave...



