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Re: -1 x -1 ?
Posted:
Sep 16, 1999 5:42 PM
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let b be the additive inverse of 1 (aka -1)
thus:
b+1 = 0
thus (squaring both sides):
(b+1)(b+1) = 0
thus (multiplying out and using commutativity)
b*b + 2b + 1 = 0
thus
b*b + b + (b + 1) = 0
thus:
b*b + b + 0 = 0
thus
b*b + b = 0
b*b is the additive inverse of b (aka 1).
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