
Re: Integer pairs in sum of reciprocals
Posted:
Jan 1, 2001 10:00 PM


saxon970@yahoo.com wrote:
> Hello. I have some questions about how to approach the problem below: > > How many pairs of positive integers a and b are there such that a < b > and > 1/a + 1/b = 1/2001 ? > > End of problem. > > Is trial and error and making a manual list the way to go? > > Thanks. > > Sent via Deja.com > http://www.deja.com/
Set a to 2001 or greater and b to a large value. The result is very close to 1/2001, where 2001 is called c,
1/a + 1/b = 1/c, or
a ^1 + b ^1 = c^1
There are probably infinite solutions.
Ross
 Ross Andrew Finlayson Finlayson Consulting Ross at TikiLounge: http://www.tikilounge.com/~raf/ "The best mathematician in the world is Maplev in Ontario."  Pertti L.

