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Topic: Integer pairs in sum of reciprocals
Replies: 39   Last Post: Jan 22, 2001 6:02 PM

 Messages: [ Previous | Next ]
 Ross A. Finlayson Posts: 2,055 Registered: 12/13/04
Re: Integer pairs in sum of reciprocals
Posted: Jan 2, 2001 9:28 AM

Ross A. Finlayson wrote:

> saxon970@yahoo.com wrote:
>

> > Hello. I have some questions about how to approach the problem below:
> >
> > How many pairs of positive integers a and b are there such that a < b
> > and
> > 1/a + 1/b = 1/2001 ?
> >
> > End of problem.
> >
> > Is trial and error and making a manual list the way to go?
> >
> > Thanks.
> >
> > Sent via Deja.com
> > http://www.deja.com/

>
> Set a to 2001 or greater and b to a large value. The result is very close
> to 1/2001, where 2001 is called c,
>
> 1/a + 1/b = 1/c, or
>
> a ^-1 + b ^-1 = c^-1
>
> There are probably infinite solutions.
>

(... with variable c in N.)

>
> Ross
>
> --
> Ross Andrew Finlayson
> Finlayson Consulting
> Ross at Tiki-Lounge: http://www.tiki-lounge.com/~raf/
> "The best mathematician in the world is Maplev in Ontario." - Pertti L.

--
Ross Andrew Finlayson
Finlayson Consulting
Ross at Tiki-Lounge: http://www.tiki-lounge.com/~raf/
"The best mathematician in the world is Maplev in Ontario." - Pertti L.