Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: Integer pairs in sum of reciprocals
Replies: 39   Last Post: Jan 22, 2001 6:02 PM

 Messages: [ Previous | Next ]
 Jan Kristian Haugland Posts: 1,303 Registered: 12/4/04
Re: Integer pairs in sum of reciprocals
Posted: Jan 4, 2001 2:39 PM

Surely you are joking???

Brian Evans wrote:

> From what I can deduce the answer is actually none.
>
> Starting at the boundary condition for where a= b :
> 1/4002 + 1/4002 = 1/2001
> Which reduces to
> 1/2 + 1/2 = 1
> Now for us to move off the boundary condition one
> of these must grow and the other shrink. Problem
> is there is no 1/x greater than 1/2 so one can not
> get any bigger.
>
> Brian Evans
>
> <saxon970@yahoo.com> wrote ...

> > Hello. I have some questions about how to approach the problem below:
> >
> > How many pairs of positive integers a and b are there such that a < b
> > and
> > 1/a + 1/b = 1/2001 ?
> >
> > End of problem.
> >
> > Is trial and error and making a manual list the way to go?

--

Jan Kristian Haugland
http://home.hia.no/~jkhaug00