"Ahmed Fares" <ahmedfares@REMOVEmy-deja.com> wrote in message news://email@example.com... > >Suppose that exactly k of the points lie on the same line > >for some k ( 2 <= k < n ). Then each of the remaining > >n - k points can be paired with each of these points leading > >to (n - k)*k distinct lines. Along with the first line this leads > >to 1 + (n-k)*k lines which is >= n for n >= 3. > > You are assuming that each line between one remaining point and one of > the k points contains only these 2 points, this is not true in general > of course. >
Yes, sorry I goofed - that's the third time this week :-() But see my corrected post - I think that's right.