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Topic: A limit for ln(x)?
Replies: 4   Last Post: Apr 28, 2001 7:01 AM

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Wade Ramey

Posts: 524
Registered: 12/6/04
Re: A limit for ln(x)?
Posted: Apr 27, 2001 5:37 PM
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In article <3AE9D37D.D138C124@yahoo.se>, Marko <kroatman@yahoo.se> wrote:

> This limit seems to give ln(x):
> lim n*(x^1/n - 1) = ln(x), x > 0.
> n->oo

Fixing x > 0, the above is the derivative of x^t wrt t at t = 0, because

n*(x^1/n - 1) = (x^1/n - x^0)/(1/n).

Recalling that d(x^t)/dt = ln(x)*x^t, putting in t = 0 gives your result.


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