
Re: integration cube root sin x
Posted:
Jul 22, 2001 1:34 AM


And BTW, Mathematica gives the indefinite integral as:
Int [(sin x)^(1/3) dx] =  cos(x)*HG2F1[1/2,1/3,3/2,(cos x)^2]*(sin x)^(4/3) / (sin x)^(4/3),
where HG2F1 is Hypergeometric2F1, defined as:
HG2F1(a,b;c;z) = sum(k=0,inf) (a_k*b_k / c_k) * z^k / k!
hth,
Doug Magnoli
Tim 923 wrote:
> Can this be expressed in elementary functions? I doubt it. > > My email address is antispammed. If you want to email me, > remove the 2 B's after hitting email reply. > > Tim 923

