
Re: integration cube root sin x
Posted:
Jul 22, 2001 1:29 AM


Are you talking about an indefinite or a definite integral? In case of the definite integral from 0 to pi/2, the beta function will give you a solution.
If I remember right, B(n,m) = 2 Int[0, pi/2, (sin x)^(2n1) (cos x)^(2m1) dx]
So int[0, pi/2, sinx^(1/3) dx] = (1/2) B(1/2, 2/3) = gamma(1/2) gamma(2/3) / gamma (7/6)
~ 2.587
Doug Magnoli
Tim 923 wrote:
> Can this be expressed in elementary functions? I doubt it. > > My email address is antispammed. If you want to email me, > remove the 2 B's after hitting email reply. > > Tim 923

