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Topic: Composites, and neat relation
Replies: 18   Last Post: Sep 14, 2004 3:38 AM

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 Dik T. Winter Posts: 7,899 Registered: 12/6/04
Re: Composites, and neat relation
Posted: Sep 12, 2004 7:24 PM

In article &lt;3c65f87.0409121043.5988edb8@posting.google.com&gt; jstevh@msn.com (James Harris) writes:
...
&gt; Using that with x = N/2kj, where N, k and j are naturals, and N&gt;=2kj,
&gt; you get
&gt; [(N+2j)/2kj] = [N/kj] - [N/2kj]
&gt; and to test it, I'll use N=13, k=2, j=3, which gives
&gt; [19/12] = [13/6] - [13/12]
&gt; so that works.

Yes, that it works for one set of values *must* mean that it works for all
sets of values... Try k = 6, j = 1, and N any of the values from 18 to 21.

Where is the null test?
--
dik t. winter, cwi, kruislaan 413, 1098 sj amsterdam, nederland, +31205924131
home: bovenover 215, 1025 jn amsterdam, nederland; <a href="http://www.cwi.nl/~dik/">http://www.cwi.nl/~dik/</a>

Date Subject Author
9/12/04 JAMES HARRIS
9/12/04 The Last Danish Pastry
9/12/04 Jim Burns
9/12/04 Tim Smith
9/13/04 David C. Ullrich
9/12/04 Nate Smith
9/12/04 C. BOND
9/12/04 Dik T. Winter
9/12/04 Dik T. Winter
9/12/04 JAMES HARRIS
9/13/04 Paul Murray
9/13/04 JAMES HARRIS
9/13/04 C. BOND
9/13/04 Jim Burns
9/14/04 Nate Smith
9/13/04 Dik T. Winter
9/14/04 Paul Murray
9/13/04 Dik T. Winter
9/13/04 David C. Ullrich