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Re: Composites, and neat relation
Posted:
Sep 13, 2004 6:11 AM


In article <3c65f87.0409121727.2ef5c7a8@posting.google.com> jstevh@msn.com (James Harris) writes: > jstevh@msn.com (James Harris) wrote in message news:<3c65f87.0409121043.5988edb8@posting.google.com>... > > So someone pointed out that there's the trivial relation > > > > [x] + [x + 1/2] = [2x] where you're in reals, > > > > and I started thinking about > > > > [x] + [x + 1/k] = [2x] > > > > also in reals, with k>1, and it turns out you need x>1 as well, which > > I was thinking about didn't put down before. > > You can have x less than 1 as what's needed is > > xk + 1 >= k
Think again. (Take x = 5/3, k = 6.)  dik t. winter, cwi, kruislaan 413, 1098 sj amsterdam, nederland, +31205924131 home: bovenover 215, 1025 jn amsterdam, nederland; <a href="http://www.cwi.nl/~dik/">http://www.cwi.nl/~dik/</a>



