Math Forum Discussions

WebMonster

Posts: 1
Registered: 1/25/05

Re: help
Posted: Jan 2, 2005 9:45 AM

Plain Text

George Cox wrote:
> WebMonster wrote:
> >
> > Hello!
> > Is this a normal equation, or a diophantine equation?
>
> It is an equation that one must "do". Isn't that enough?
>

Hi, Ok I try to solve it.
So, we have an equation:
2x-4y=16

Now order y to the right side, and "anything other" to the left side:
0.5x-8=y

This is a simple linear function
[http://www.apaczai.elte.hu/~08amszbb/func.PNG]. Now make a product
from the left side:
0.5*(x-4)=y

Examine the domain (D) and the range (R) of the function. The domain is
the set of real numbers, and the range is the set of real numbers
evenly divisible with 0.5. So there are infinity x values, because
there are infinity real numbers evenly divisible with 0.5, and because
of this, there are infinity y values, and because of this there are
infinity pairs of x and y values, and because of this there are
infinity solutions of the equation.

I hope I helped, my english is poor especially on terminologies
Bence Szasz

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