Sylvain Croussette answered on alt.math.undergrad: > st9468s4 (EJC)@drexel.edu wrote:
> ABC I have to find the values of A, B and C where A>B>C >- CBA >_________ >= CAB
Assuming A,B and C are single digits: Rewrite as: CAB +CBA -------- ABC
>From the 1st column: B+A=C, or B+A=C+10, if there is a carry. From the 2nd column also A+B=B; this is the same as the 1st column so it's impossible, unless there is a carry from the 1st; so it's 1+A+B=B+10, because A+B produced a carry in the 1st column. From the third column 1+C+C=A. Rewrite these equations: 1) A+B-C=10 2) A+B-B=9 3) A-2C=1 Clearly from equation 2, A=9, so from equation 3, C=4 so B=5.