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ticbol
Posts:
116
Registered:
1/25/05


Re: calc help
Posted:
Jan 21, 2005 3:07 PM


INT.[x(4 2x^2)^(1/2)]dx
Let u = (4 2x^2) So, du = 4x dx And (4 2x^2)^(1/2) = u^(1/2) Then, INT.[x(4 2x^2)^(1/2)]dx = INT.[(4 2x^2)^(1/2)]x dx = INT.[(4 2x^2)^(1/2)](4/4)x dx = (1/4) INT.[(4 2x^2)^(1/2)](4x dx) = (1/4)INT.[u^(1/2)]du = (1/4)[1/(3/2)*(u^(3/2))] +C = (1/4)(2/3)u^(3/2) +C = (1/6)u^(3/2) +C = (1/6)(4 2x^2)^(3/2) +C answer.
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