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Replies: 5   Last Post: Jan 24, 2005 2:20 AM

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 aaronhunter@gmail.com Posts: 3 Registered: 1/29/05
Posted: Jan 22, 2005 10:09 PM

Hello. I have the following expression. I have got it figured out
except I am missing a minor detail that is causing me to have 2x+1

Note that x^1 is (x to the first power) ^-(1/2) is to the negative 1/2
power etc...

Problem: [x(x+2)^-(1/2) + (x+2)^(1/2) ] / (x+2)^(3/2)

I first separate out the problem and combine the lower exponents to get
[x((2/(x+2)) + 1/(x+2)] / (x+2)

Then I distribute the x
[2x/(x+2) + 1/(x+2)] / (x+2)

Now combine like terms
[(2x+1)/(x+2)] / (x+2)

Now multiply
[(2x+1)/(x+2)] * 1/(x+2)

my final result is
2x+1 / (x+2)^2
What step am I missing to get quantity 2(x+1) / (x+2)^2???

Thanks!

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Date Subject Author
1/22/05 aaronhunter@gmail.com
1/24/05 Jeffrey Turner
1/24/05 ticbol
1/24/05 Bob
1/24/05 George Cox
1/24/05 Rob Morewood