> Hello. I have the following expression. I have got it figured out > except I am missing a minor detail that is causing me to have 2x+1 > instead of 2(x+1) in my final numerator. Please help! > > Note that x^1 is (x to the first power) ^-(1/2) is to the negative 1/2 > power etc... > > Problem: [x(x+2)^-(1/2) + (x+2)^(1/2) ] / (x+2)^(3/2) > > I first separate out the problem and combine the lower exponents to get > [x((2/(x+2)) + 1/(x+2)] / (x+2)
You've got a mistake here already, try taking the part within the original square brackets and combining it into a single fraction. You should be able to get it in terms of (ax+b)/(x+2)^(1/2).
> Then I distribute the x > [2x/(x+2) + 1/(x+2)] / (x+2) > > Now combine like terms > [(2x+1)/(x+2)] / (x+2) > > Now multiply > [(2x+1)/(x+2)] * 1/(x+2) > > my final result is > 2x+1 / (x+2)^2 > What step am I missing to get quantity 2(x+1) / (x+2)^2??? > > Thanks!
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