Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Replies: 5   Last Post: Jan 24, 2005 2:20 AM

 Messages: [ Previous | Next ]
 ticbol Posts: 116 Registered: 1/25/05
Posted: Jan 24, 2005 2:18 AM

Look at this:

[x(x+2)^-(1/2) + (x+2)^(1/2) ] / (x+2)^(3/2)

We clear the negative exponent,
= [x/(x+2)^(1/2) + (x+2)^(1/2) ] / (x+2)^(3/2)

We simplify those inside the bracket,
= [{x +(x+2)^(1/2)* (x+2)^(1/2)} / {(x+2)^(1/2)} ] / (x+2)^(3/2)
= [{x +(x+2)^1} / {(x+2)^(1/2)} ] / (x+2)^(3/2)
= [{x +x+2} / {(x+2)^(1/2)} ] / (x+2)^(3/2)
= [{2x +2} / {(x+2)^(1/2)} ] / (x+2)^(3/2)
= [{2(x+1)} / {(x+2)^(1/2)} ] / (x+2)^(3/2)

We carry on,
= [{2(x+1)} / {(x+2)^(1/2)} ] * [1/ (x+2)^(3/2)]
= [2(x+1)] / [{(x+2)^(1/2)} * {(x+2)^(3/2)}]
= [2(x+1)] / [(x+2)^(4/2)]

--
submissions: post to k12.ed.math or e-mail to k12math@k12groups.org
private e-mail to the k12.ed.math moderator: kem-moderator@k12groups.org
newsgroup website: http://www.thinkspot.net/k12math/
newsgroup charter: http://www.thinkspot.net/k12math/charter.html

Date Subject Author
1/22/05 aaronhunter@gmail.com
1/24/05 Jeffrey Turner
1/24/05 ticbol
1/24/05 Bob
1/24/05 George Cox
1/24/05 Rob Morewood