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Re: 3D Geometery
Posted:
Apr 24, 2005 8:28 AM
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"" wrote in alt.algebra.help:
>I think you may have misunderstood what the question is asking, so here
>is the question verbatim.
Finally!
(When you didn't post the actual question, it is hardly fair to say
that Paul or anyone else "may have misunderstood what the question
is asking".)
>Let l and m be the lines
>( x - 1 )/2 = ( y - 2 )/3 = ( z - 1 )/3
>and
>( x - 3 )/3 = ( y - 1 )/2 = ( z - 1 )/4
>respectively.
>(i) Find the equations of planes P and Q that do not intersect, and
>have the property that l lies in P and m lies in Q.
>(ii) Find the point on Q that is closest to (1, 2, 1), and hence find
>the equation of the line l' in Q that is parallel to l.
>(iii) Explain why the point of intersection of l' and m is the point on
>m that is closest to l, and find this point. Find also the distance
>from this point to the point on l closest to it.
>
>I have calculated the coordinates of all the lines, planes and points
Yes? What are those equations, please?
--
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
http://OakRoadSystems.com/
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