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Topic: Reason for operator precedence
Replies: 15   Last Post: Mar 15, 2006 8:56 AM

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Dik T. Winter

Posts: 7,899
Registered: 12/6/04
Re: Reason for operator precedence
Posted: Mar 15, 2006 8:56 AM
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In article <dv6nv8$chc$1@agate.berkeley.edu> magidin@math.berkeley.edu (Arturo Magidin) writes:
...
[ Without operator precedence ]
...
> If you want to put in the square, you
> would need to do something like
>
> bx + c + (a(x^2)).
>
> Higher degree polynomials would be even harder.


It can be done:
a * x + b * x + c
(thanks to Horner), but it is not immediately clear that it is a
polynomial.
--
dik t. winter, cwi, kruislaan 413, 1098 sj amsterdam, nederland, +31205924131
home: bovenover 215, 1025 jn amsterdam, nederland; http://www.cwi.nl/~dik/




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