Matt wrote: > A box contains a penny, a nickle, a dime, and a quarter. A coin is > drawn at random and not replaced. A second coin is then drawn. How > many outcomes are possible? > > a. 25 > b. 12 > c. 5 > d. 4 > > How do you figure this? Thanks for your time and patience. > > Best wishes, > > Matt >
How many possibilities are there on the first draw? If you don't replace the first coin, how many possibilities are left on the second draw? Multiply those two numbers to get the number of possible outcomes.
-- Bruce Weaver email@example.com www.angelfire.com/wv/bwhomedir