[added "JSH:" to subject, spared sci.crypt and alt.math]
[email@example.com] > ... > And it has been posted in this thread that I DID get it wrong. > > If you do it right, it shows a dependency on the factorization of T, > which is no good. > > But what if you go the other way, isolating y on the right side, > instead of z?
> So instead, you would complete the square twice isolating z on the left > and with the second you would get y inside the square on the right. > > The reason for wondering is that if you solve for z using the four > linear equations, yup, it does solve in such a way that you can have a > difference of factors of T, but y does not. > > Long-shot.