Search All of the Math Forum:
Views expressed in these public forums are not endorsed by
Drexel University or The Math Forum.



Re: Trapazoid geometry
Posted:
Aug 7, 2006 8:01 AM


Lets assume that the angles are labeled, so you know which go with which side.
(i) If you have one side (base) and the two adjacent angles to it, then generally, these will lead to two rays. Assuming these are not parallel, then each line parallel to the base will have a unique length     and the length of the other parallel side will determine a unique height.
(ii) Of course, if the two rays you created above are parallel, then the two parallel sides are equal and there is no unique height.
In case (i) where the lines intersect, then you can:     find the height of the point of intersection (using trig);     use the ratio of the two lengths of the parallel sides to scale the height from the vertex to the second side;     subtract these two heights to get the perpendicular height between the two parallel sides.
It is easy to see how this process breaks down completely, in case (ii).
Walter Whiteley
On 4Aug06, at 10:19 PM, tompy97 wrote:
i have a trapazoid of which i know the lengths of the two paralel sides and all of the angles, is there any way to find the perpendicular height



