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Topic: squaring a circle
Replies: 18   Last Post: Jan 3, 2012 12:22 PM

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Eur Ing Panagiotis Stefanides

Posts: 567
Registered: 12/3/04
Re: squaring a circle
Posted: Dec 14, 2003 10:50 AM
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On 13 Dec 2003, Mensanator wrote:
>>Subject: squaring a circle
>>From: (vsvasan)
>>Date: 12/13/2003 10:01 AM Central Standard Time
>>Message-id: <>
>> Sub: Unsolvabve Geometrical Problems
>> Squaring a given circle is unsolvable .

>And its unsolvabilty has been proven.

One has to digest this alleged "proof".
Have You?
I tried to follow those guys who made Marathons
to succeed this goal as they could not reach the " Sour Grapes".
What some of them devised light-heartedly ,the invention
and use(God knows how-The King is Naked...)of the HALF PART
of EULERS Equation:
but for JUSTICE to prevail since EULER'S Equation
states that: e^(iPi)=cos(pi)+i[sin(pi)]
then e^(ipi)=-1 + i(0) , thus the
other solution is e^(ipi)=0.

So take Your pick!
This is what this group of guys did not take into consideration!
Panagiotis Stefanides

>>There are volumes of pages on the
>>subject which I have read - from Archimedes to SrinivasaRamanujan.

>And none of them proved it. So what?

>> Well! I have found out a solution.
>No, you haven't.

>>Could not believe it ?
>Belief is irrelevant. It's been proven impossible.

>>My logic is very simple.
>And wrong.

>>"Pi" is an irrational number.
>It's also transcendental.

>>So is square root of 2.
>But the square root of 2 is _not_ transcendental. Look up the difference.

>>There is a simple
>>geometrical construction to solve for square root of 2.

>Nobody said that was impossible.

>>Similarly I have
>>developed a simple geometrical construction to solve for "pi".

>If you constructed it, what you have is _not_ pi, because pi cannot be

>> My question is Where to send it?
>The circular file.

>>Is there any Maths Forum where I can
>>present my papers and answer questions of the experts?

>Sure, right here on sci.math. But instead of crowing about your proof, try
>asking for
>help in understanding why it's wrong.

>> May I request you to kindly guide me in this regard.

>Sorry, I wouldn't be able to find your fallacy even though I know it exists.

>>Thank you

>Ace of Clubs

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