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Topic: complex numbers
Replies: 8   Last Post: Jan 31, 2007 7:33 PM

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Faton Berisha

Posts: 39
Registered: 1/9/07
Re: complex numbers
Posted: Jan 31, 2007 7:33 PM
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On Jan 31, 11:28 pm, "" <> wrote:
> If z = r*e^(iw) [0 <= w , 2 pi], then 1/z = (1/r)e^(-iw), so Re(1/z) =
> (1/r)cos(w), 0 <= w < 2 pi. Thus, if C is real and positive the curve
> is r = cos(w)/C. As w goes from 0 to 2 pi this traces out two circles
> of diameter 1/C, one centered at (1/2/C,0) and the other at (-1/2/C,
> 0).

Ha?! Why don't you try it? If z traced the circle with center (-1/
(2C), 0)
and radius 1/(2C), then the original equation Re(1/z) = C
would be satisfied for z = -1/C.
But Re(1/(-1/C)) = -C =/= C.

> R.G. Vickson

Faton Berisha

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