The Math Forum



Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.


Math Forum » Discussions » sci.math.* » sci.math

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: complex numbers
Replies: 8   Last Post: Jan 31, 2007 7:33 PM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]
Faton Berisha

Posts: 39
Registered: 1/9/07
Re: complex numbers
Posted: Jan 31, 2007 7:33 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

On Jan 31, 11:28 pm, "C...@shaw.ca" <C...@shaw.ca> wrote:
>
> If z = r*e^(iw) [0 <= w , 2 pi], then 1/z = (1/r)e^(-iw), so Re(1/z) =
> (1/r)cos(w), 0 <= w < 2 pi. Thus, if C is real and positive the curve
> is r = cos(w)/C. As w goes from 0 to 2 pi this traces out two circles
> of diameter 1/C, one centered at (1/2/C,0) and the other at (-1/2/C,
> 0).


Ha?! Why don't you try it? If z traced the circle with center (-1/
(2C), 0)
and radius 1/(2C), then the original equation Re(1/z) = C
would be satisfied for z = -1/C.
But Re(1/(-1/C)) = -C =/= C.

>
> R.G. Vickson
>

Faton Berisha




Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.