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Re: x^2 - Ay^2 =1
Posted:
May 29, 2007 7:12 AM
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Vincenzo Librandi wrote:
>
> for the all Pell's equation
> X^2-Ay^2=1
> y=(n+sqrt(A*n^2-(A-1))=0 mod(A-1)
>
> then for X^2-421Y^2=1
> y=(n+sqrt(421n^2-420))=0 mod(420)
>
Philippe wrote:
>>
>>So this method seems of little help as we have to >>solve the Pell's equation in order to hmm ... 'may be' >>solve it !
Remenber who it may come in useful
because for the first n>1 have the
fundamental with x=y+n.
Regards
Vincenzo Librandi
vincenzo.librandweoz@alice.it
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