
Re: Largest primeproduct with 2 as factor?
Posted:
Aug 15, 2007 6:55 PM


On Aug 15, 5:42 pm, Randy Poe <poespamt...@yahoo.com> wrote: > On Aug 15, 6:36 pm, jonas.thornv...@hotmail.com wrote: > > > > > > > On 16 Aug, 00:18, stephane.fr...@gmail.com wrote: > > > > On Aug 15, 3:03 pm, jonas.thornv...@hotmail.com wrote: > > > > > On 16 Aug, 00:00, stephane.fr...@gmail.com wrote: > > > > > > On Aug 15, 2:53 pm, jonas.thornv...@hotmail.com wrote: > > > > > > > I do not know much math, i just wonder if there is a largest > > > > > > primeproduct with two as one of the factors. > > > > > > Same i wonder for three. > > > > > > > If not..., but if so is it true for any primefactor used in > > > > > > primeproduct that they will have a range? > > > > > > Do every factor have a range in primeproducts? > > > > > > > A pure guess tell me that the numbers of primeproducts with 2 or 3 > > > > > > used as one of the factor is infinite but i am not sure. > > > > > > > JT > > > > > > You guess is right. This is because there is infinity prime number > > > > > then if N is the bigger prime product, you will find A your biggest > > > > > prime with A = N/2. You can find a prime number A' with A'> A, then N' > > > > > = A x 2 > N. Same rules with 3 or any prime numbers. > > > > > > SF > > > > > Could anyone tell me the biggest "known" primeproduct that has two as > > > > factor? Hide quoted text  > > > > >  Show quoted text  > > > > Well dude , you can suppose you got one and then prove that you can a > > > bigger one . D?lj citerad text  > > > >  Visa citerad text  > > > Ok an easy question i do not have any primeproduct algorithm going, so > > i would be interested in a list of primeproducts less than a million > > that has two as factor? > > > Can not be that many or? > > > If not that many would be nice for 10 000 000 and for 100 000 000? > > > Well if already a million would have couple of 100 i am not that > > interested in the bigger numbers. > > What do you mean by "primeproduct"? Do you mean any > number that has 2 as a factor?
Maybe he means a single factor of 2?
So that it would have to be congruent to 2 (mod 4).
> > For instance, does 2^20 = 1048576 qualify as a "primeproduct"? > > If you just mean any number that has two as a factor, > these are called "even numbers", and any number that > ends in 0, 2, 4, 6, or 8 is such a number.
2 (mod 4) would be 2, 6, 10, 14, 18, ...
> Thus, here > is a large even number: 7924720394820394812476 > > I guarantee that has 2 as a factor.
>>> print digits(7924720394820394812476,2) 1101011011001100110010110100011000001111011111010111110100000010000111100
Two factors of 2.
> >  Randy

