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Topic: An Argument for the Subroot Node
Replies: 28   Last Post: Mar 14, 2008 8:32 PM

 Messages: [ Previous | Next ]
 Tony Orlow Posts: 3,142 Registered: 8/23/06
Re: An Argument for the Subroot Node
Posted: Mar 11, 2008 1:24 PM

G. Frege wrote:
> On Tue, 11 Mar 2008 16:51:03 +0100, G. Frege <nomail@invalid> wrote:
>
> Oopos... typo/thinko...
>

>>> According to it, the perimeter of a triangle is a tree...
>>> which, of course, it is not.
>>>

>> Wait a second. If the nodes of your triangle were, say a, b, c then
>> (say) a, b would be connected by more than one path:
>>
>> p_1 = ((a,b))
>>
>> p_2 = ((a,b), (b,c), (c,a), (a,b))
>>

> No?
>
>
> F.
>

a and b are connected by ((a,b)) and ((a,c),(c,b)), two simple paths,
and thus there exists a cycle.

T.

Date Subject Author
3/11/08 Tony Orlow
3/11/08 Virgil
3/11/08 G. Frege
3/11/08 Tony Orlow
3/11/08 Virgil
3/11/08 Tony Orlow
3/11/08 Virgil
3/11/08 G. Frege
3/11/08 J. Antonio Perez M.
3/11/08 G. Frege
3/11/08 G. Frege
3/11/08 Tony Orlow
3/11/08 briggs@encompasserve.org
3/14/08 Tony Orlow
3/14/08 David R Tribble
3/14/08 LudovicoVan
3/11/08 Tony Orlow
3/11/08 J. Antonio Perez M.
3/11/08 Tony Orlow
3/11/08 Tony Orlow
3/11/08 Tony Orlow
3/11/08 LudovicoVan
3/11/08 LudovicoVan
3/14/08 Tony Orlow
3/14/08 LudovicoVan
3/14/08 LudovicoVan
3/11/08 David R Tribble
3/11/08 LudovicoVan
3/11/08 LudovicoVan