Driveby
Posts:
11
Registered:
11/27/07


Re: Proving trigonometric identities
Posted:
Jan 26, 2009 12:07 PM


On Sun, 25 Jan 2009 21:49:25 0800 (PST), Albert <albert.xtheunknown0@gmail.com> wrote:
>On Jan 24, 9:02 pm, Albert <albert.xtheunkno...@gmail.com> wrote: >> I agree: assuming sin x = 3 /4 is a step that one should get to (or >> take the inverse cosec early on), x = 229, 311 degrees to the nearest >> degree. > >The solve function on my calculator returns a strange answer, which >indicates that there aren't actually any solutions to the original >question 3cosec x + 4 = 0. >So why doesn't it have any solutions?
How could someone know what you and your calculator are doing?
3 csc(x) + 4 = 0 has two zeros in [0, 2 pi),
x = pi + asin(3/4) and x = 2*pi  asin(3/4)

