khoo
Posts:
63
Registered:
8/9/08
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Re: How to calculate the angle between two images?
Posted:
Apr 5, 2009 9:54 AM
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> > the max_angle i find is 1 every time..but when i check im8 value, got other value max than 1..so how i need to do the find the peak value?
>
> The correlation you should get from doing the Re(IFFT ....) is a one dimensional graph, whereas the max(max... you are applying is for a 2 dimensional matrix.
>
> Try to plot what you have called im8 and see if you end up with a graph showing a peak.
>
> When I try to access your image I get a message indicating it has been deleted or removed.
> > Sorry about your dead line, but it is Sunday here, and it is only just luck I caught this mail, as I have family responsibilities to deal with on a weekend.
>
> Good Luck & Regards
>
> Dave Robinson
Bro Dave, this is the code i do until currently...the max value i find is very large...i no sure i got do what wrong o not...but pls teach me how to find the correct angle..
clear all;clc
im1=imread('image1.jpg');
im11=rgb2gray(im1);
im111=im2double(im11);
[dx,dy]=gradient(im111);
p1=atan2(dy,dx);
im1111=edge(p1,'canny');
bw1 = bwmorph(im1111,'dilate');
im11111=p1.*bw1;
im6=hist(im11111);
im66=fft(im6);
im=imread('image2.jpg');
im2=imresize(im,size(im11),'bicubic');
im22=rgb2gray(im2);
im222=im2double(im22);
[dx,dy]=gradient(im222);
p2=atan2(dy,dx);
im2222=edge(p2,'canny');
bw2 = bwmorph(im2222,'dilate');
im22222=p2.*bw2;
%subplot(2,1,2);hist(im22222);
im7=(hist(im22222));
im77=conj(fft(im7));
im8=real(ifft(im66.*im77));
im9=transform(im8);
max_value=max(im9)
hist(im8);
below is the function i try to convert the image to 1 Dimensional matric
function b=transform(a)
[row,column]=size(a);
b=[];
for i=1:row
for j=1:column
b=[b a(i,j)];
end
end
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