Laurel wrote: > I have 2 similar triangles. JKL is similar PQR. > PQR= > QR=x > RP=84 > Height=y > > JK=13 > KL=13 > LJ=24 > Height=5 > > Question: > a. Find the scale factor of JKL to PQR and the values of x and y > b. Find the perimeters of both triangles. > c. Find the area of both triangles. > d. Compare the ratio of perimeters to the ratios of area of JKL to PQR. what do you notice?
Hi, Here are my thoughts.
84/24 = 3.1/1 JKL PQR x = 3.5(13) y = 3.5(5) = 45.5 = 17.5
Area = 1/2(5)(5) Area = 1/2(17.5)(17.5) = 32.5 = 398.125
Per. = 13+13+24 Per. = 45.5+45.5+84 = 50 = 175
175/50 = 3.5 _____________________
Please let me know how I did. I'm really getting too old for this, even my hair hurts.