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Re: Conjecture Prime
Posted:
Jun 25, 2009 2:25 AM


> 2n * 2 (n+1)  1 is prime > > it's pretty easy to show if n = 1 or 5 (mod 7) then 7 > will divide the > whole thing
I never wrote this:
> 2n * 2 (n+1)  1 is prime
I write: [[N*N]*([N*N]+2)]1



