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Topic: Prime Generalization Conjecture
Replies: 48   Last Post: Nov 7, 2017 5:14 PM

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 Guest
Re: Musatov Prime Generalization Conjecture
Posted: Jun 30, 2009 1:12 AM

Martin Musatov wrote:
Peter Nilsson wrote:
> Richard Heathfield <r...@see.sig.invalid> wrote:
> > CBFalconer said:
> > > Richard Heathfield wrote:
> > > > MeAmI.org said:
> > > > > RULE: EVERY PRIME number is exactly
> > > > > 1/2 of some other number +1.

>
> Every prime is exactly half of +1?!
>

> > > >
> > > > 2 is a counter-example unless "other number" can mean "same
> > > > number".

> > >
> > > Oh? 3 is 'another number'. 3+1 = 4 (usually). 4/2 = 2 (usually).

> >
> > Division has precedence over addition. Even if it didn't,
> > associativity would be left to right unless specified otherwise.

>
> If I have 4 dollars and 20 cents, what is half the dollars and cents?
>
> a) \$1.20
> b) \$2.10
> c) \$2.20
> d) \$2.40
>
> --
> Peter

Dear Peter,

allow me a brief moment to clarify my conjecture:

"Musatov's Prime Generalization Conjecture": Every prime greater than
2 is 2n+1=P.

2*1+1=3
2*2+1=5
...
2*20+1=41
...

(1)Is my conjecture provable?

Peter, the answer to the question is "b)2.10".

But please bear with me and consider the following scenario:

Suppose I have three quantities of loose coins:

1) \$0.50
2) \$0.40
3) \$0.60

The sum of the three quantities is \$1.50.

Now suppose we are multiplying those same three quantities of coins:

\$0.50*\$0.40*\$0.60

.50*.40=.20

And...

.20*.60=\$0.12.

(2)Why should multiplying our money result in a loss of \$1.38 or a 92%
loss?

If the three sums were dollars the case would be different.

\$50+\$40+\$60=\$150
\$50*\$40+\$60=\$1200

I do understand how to solve the problem literally, but chose to show
this example to prove decimal representations fail basic rationale.

++
Musatov

Date Subject Author
6/20/09 MeAmI.org
6/20/09 Richard Heathfield
6/20/09 CBFalconer
6/21/09 Richard Heathfield
6/26/09 MeAmI.org
6/26/09 John H. Guillory
6/26/09 Guest
6/26/09 Richard Heathfield
6/27/09 Guest
6/27/09 Guest
6/27/09 Guest
6/29/09 Peter Nilsson
6/30/09 Guest
6/30/09 Alf P. Steinbach
6/30/09 Richard Heathfield
6/30/09 Guest
6/30/09 Dik T. Winter
6/30/09 Richard Heathfield
6/30/09 Guest
6/30/09 Richard Heathfield
6/30/09 mike
6/30/09 Richard Heathfield
6/30/09 Guest
9/13/13
9/13/13
7/7/09 Constructive Truth
7/8/09 Alan Morgan
9/13/13
7/8/09 Guest
7/8/09 Guest
7/8/09 mike
7/8/09 Constructive Truth
7/8/09 Constructive Truth
7/12/09 mike
7/13/09 Guest
7/15/09 Guest
8/24/09 Guest
8/24/09 Guest
6/30/09 Guest
6/30/09 Ed Prochak
11/7/17 4musatov@gmail.com
6/20/09 William Elliot
6/20/09 Guest
6/20/09 Guest
6/20/09 Guest
6/20/09 Guest
6/20/09 Guest
2/8/14
9/13/13