mike
Posts:
34
Registered:
10/29/08


Re: Musatov Prime Generalization Conjecture
Posted:
Jul 8, 2009 10:01 PM


In article <88f7a7fc702c47ac8f3e66088faf4487 @z4g2000prh.googlegroups.com>, marty.musatov@gmail.com says... > > Here are a list of statements, I would like to know if we can > properly > decide from 2 N + 1: > > (All of the below statements assume P > 2, as you asserted.) > > Can we say....? (If every prime > 2 is 2 N + 1 = odd) > > 1. 2 N + 1 = P an (odd) prime 1/2 (of an even) 2P?
I assume that you trying to state:
For all primes P of the form P = 2*N + 1, the number 2*P is even.
If so then it is trivially true by definition. > > 2. Can we then write for every prime > 2: > > 2 N + 1 = P (odd) and 2P (Even), N is also always > even?
Here you appear to be stating: For all P > 2, P = 4*N + 1, for some natural number N.
If so then this is trivially false as it doesn't hold true for 7.
> > 3. Can the above statement equivocally be stated: > > 2 (even N) + 1 = Every Prime > 2 = 1/2 2P or 1/2 * 4 (even > N) + 2? > > 2 * 8 + 1 = 17 (a prime) = 1/2 (17*2) or 1/2 * (4 * 8) + > 2 ?
This seems teh same as 2 above. If so then it is false.
Marty, it may interest you to note that as well as:
For all P > 2, P = 2*N + 1
being true, it is also the case that:
For all P > 3, P = 6*N +/ 1
 Mike

