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Topic: Prime Generalization Conjecture
Replies: 47   Last Post: Feb 8, 2014 8:41 PM

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 mike Posts: 34 Registered: 10/29/08
Re: Musatov Prime Generalization Conjecture
Posted: Jul 8, 2009 10:01 PM

In article <88f7a7fc-702c-47ac-8f3e-66088faf4487
>
> Here are a list of statements, I would like to know if we can
> properly
> decide from 2 N + 1:
>
> (All of the below statements assume P > 2, as you asserted.)
>
> Can we say....? (If every prime > 2 is 2 N + 1 = odd)
>
>          1. 2 N + 1 = P an (odd) prime 1/2 (of an even) 2P?

I assume that you trying to state:

For all primes P of the form P = 2*N + 1, the number 2*P is even.

If so then it is trivially true by definition.
>
>           2. Can we then write for every prime > 2:
>
>                2 N + 1 = P (odd) and 2P (Even), N is also always
> even?

Here you appear to be stating:
For all P > 2, P = 4*N + 1, for some natural number N.

If so then this is trivially false as it doesn't hold true for 7.

>
>           3. Can the above statement equivocally be stated:
>
>    2 (even N) + 1 = Every Prime > 2 = 1/2 2P or 1/2 * 4 (even
> N) + 2?
>
>           2 * 8 + 1 = 17 (a prime) = 1/2 (17*2) or 1/2 * (4 * 8) +
> 2 ?

This seems teh same as 2 above. If so then it is false.

Marty, it may interest you to note that as well as:

For all P > 2, P = 2*N + 1

being true, it is also the case that:

For all P > 3, P = 6*N +/- 1

-- Mike

Date Subject Author
6/20/09 MeAmI.org
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