In article <88f7a7fc-702c-47ac-8f3e-66088faf4487 @z4g2000prh.googlegroups.com>, firstname.lastname@example.org says... > > Here are a list of statements, I would like to know if we can > properly > decide from 2 N + 1: > > (All of the below statements assume P > 2, as you asserted.) > > Can we say....? (If every prime > 2 is 2 N + 1 = odd) > > 1. 2 N + 1 = P an (odd) prime 1/2 (of an even) 2P?
I assume that you trying to state:
For all primes P of the form P = 2*N + 1, the number 2*P is even.
If so then it is trivially true by definition. > > 2. Can we then write for every prime > 2: > > 2 N + 1 = P (odd) and 2P (Even), N is also always > even?
Here you appear to be stating: For all P > 2, P = 4*N + 1, for some natural number N.
If so then this is trivially false as it doesn't hold true for 7.
> > 3. Can the above statement equivocally be stated: > > 2 (even N) + 1 = Every Prime > 2 = 1/2 2P or 1/2 * 4 (even > N) + 2? > > 2 * 8 + 1 = 17 (a prime) = 1/2 (17*2) or 1/2 * (4 * 8) + > 2 ?
This seems teh same as 2 above. If so then it is false.
Marty, it may interest you to note that as well as: