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Topic: ask a Q for help!
Replies: 5   Last Post: May 24, 2010 2:53 AM

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Torsten Hennig

Posts: 2,381
Registered: 12/6/04
Re: ask a Q for help!
Posted: May 20, 2010 4:24 AM
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> hi,friend:
> an equation (about r,k. m is a constant number):
> r): 2m^2+3m+1=2rm+k,here m,r,k are all positive
> integers.i test (m,r,k) many times,and find that r,k
> have the only one solution: r=k=m+1. but i cannt
> prove my guess.who can help me? thanks


This is one equation in two unknowns - so it will
in general have arbitrary many solutions for r and k.
E.g. fix r>0 arbitrary such that 2rm < 2m^2+3m+1.
Then (r,k=2m^2+3m+1-2rm) is a solution.

Best wishes
Torsten.



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